Hỗn hợp X gồm anđehit malonic, vinyl fomat, ancol...

A

- Hướng dẫn giải

Phương pháp giải:

anđehit malonic: OHC-CH₂-CHO (C₃H₄O₂)

vinyl fomat: HCOOCH=CH₂ (C₃H₄O₂)

ancol etylic: C₂H₆O

ancol anlylic: CH₂=CH-CH₂-OH (C₃H₆O)

Từ CTCT ta nhận thấy anđehit malonic và vinyl fomat có CTPT giống nhau nên ta coi như chúng là một chất.

\(\begin{gathered}
4,82(g)\,X\left\{ \begin{gathered}
{C_3}{H_4}{O_2}:x \hfill \\
{C_2}{H_6}O:y \hfill \\
{C_3}{H_6}O:z \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
72x + 46y + 58z = {m_X} \hfill \\
\xrightarrow{{BTC}}3x + 2y + 3z = {n_{C{O_2}}} \hfill \\
\xrightarrow{{BTH}}4x + 6y + 6z = 2{n_{{H_2}O}} \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
x = ? \hfill \\
y = ? \hfill \\
z = ? \hfill \\
\end{gathered} \right. \hfill \\
\to {n_{Ag}} = 4x = ? \to {m_{Ag}} = ? \hfill \\
Ty\,le:4,82(g)\,X\xrightarrow{{ + AgN{O_3}}}?(g)Ag \hfill \\
\,\,\,\,\,\,\,\,\,\,\,\,\,7,23(g)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to ?(g) \hfill \\
\end{gathered} \)

Giải chi tiết:

anđehit malonic: OHC-CH₂-CHO (C₃H₄O₂)

vinyl fomat: HCOOCH=CH₂ (C₃H₄O₂)

ancol etylic: C₂H₆O

ancol anlylic: CH₂=CH-CH₂-OH (C₃H₆O)

\(\begin{gathered}
4,82(g)\,X\left\{ \begin{gathered}
{C_3}{H_4}{O_2}:x \hfill \\
{C_2}{H_6}O:y \hfill \\
{C_3}{H_6}O:z \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
72x + 46y + 58z = 4,82 \hfill \\
3x + 2y + 3z = {n_{C{O_2}}} = 0,22 \hfill \\
4x + 6y + 6z = 2{n_{{H_2}O}} = 0,42 \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
x = 0,03 \hfill \\
y = 0,02 \hfill \\
z = 0,03 \hfill \\
\end{gathered} \right. \hfill \\
\to {n_{Ag}} = 4x = 4.0,03 = 0,12(mol) \to {m_{Ag}} = 12,96(g) \hfill \\
Ty\,le:4,82(g)\,X\xrightarrow{{ + AgN{O_3}}}12,96(g)Ag \hfill \\
\,\,\,\,\,\,\,\,\,\,\,\,\,7,23(g)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to 19,44(g) \hfill \\
\end{gathered} \)

Đáp án A