Tìm x biết  

D

- Hướng dẫn giải

Đáp án D

$$\begin{gathered} \left(x+\frac{1}{4}-\frac{1}{3}\right):\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46} \\ =\left(x+\frac{1}{4}-\frac{1}{3}\right):\frac{23}{12}=\frac{7}{46} \\ x+\frac{1}{4}-\frac{1}{3}=\frac{7}{46}.\frac{12}{23} \\ x+\frac{1}{4}-\frac{1}{3}=\frac{7}{24} \\ x=\frac{7}{24}-\frac{1}{4}+\frac{1}{3} \\ x=\frac{3}{8} \end{gathered}$$

Vậy $x = \frac{3}{8}$.